Question

a sample of gas y occupies 500 l at the pressure of 80 kpa. after changing the volume of the sample, the pressure of it is 400 kpa. what is the new volume of the gas? l

Explanation:

Step1: Recall Boyle's Law

Boyle's Law states that \(P_1V_1 = P_2V_2\) (for a given amount of gas at constant temperature), where \(P_1\) and \(V_1\) are the initial pressure and volume, and \(P_2\) and \(V_2\) are the final pressure and volume.

Step2: Substitute the given values into the formula

We are given \(P_1=80\space KPa\), \(V_1 = 500\space L\), and \(P_2=400\space KPa\). Substituting into \(P_1V_1 = P_2V_2\), we get \(80\times500=400\times V_2\).

Step3: Solve for \(V_2\)

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Answer:

\(100\)