Question

a sample of a gas (5.0 mol) at 1.0 atm is expanded at constant temperature from 10.0 l to 15.0 l. the final pressure is ____ atm.

Explanation:

Step1: Apply Boyle's Law

Boyle's Law states \(P_1V_1 = P_2V_2\) (constant \(n\), \(T\)). Here, \(P_1 = 1.0\) atm, \(V_1=10.0\) L, \(V_2 = 15.0\) L.

Step2: Solve for \(P_2\)

Rearrange the formula to \(P_2=\frac{P_1V_1}{V_2}\). Substitute values: \(P_2=\frac{1.0\ \text{atm}\times10.0\ \text{L}}{15.0\ \text{L}}\).
Calculate \(P_2=\frac{10}{15}\ \text{atm}\approx0.67\ \text{atm}\).

Answer:

\(0.67\ \text{atm}\)