Question

to rent a certain meeting room, a college charges a reservation fee of $18 and an additional fee of $5 per hour. the chemistry club wants to spend at most $73 on renting the room. what are the possible numbers of hours the chemistry club could rent the meeting room? use t for the number of hours. write your answer as an inequality solved for t.

Explanation:

Step1: Set up the inequality

The total cost is the reservation fee plus the cost per - hour times the number of hours. The reservation fee is $18$ and the cost per hour is $5$, and the club wants to spend at most $73$. So the inequality is $18 + 5t\leqslant73$.

Step2: Subtract 18 from both sides

To isolate the term with $t$, we subtract 18 from both sides of the inequality: $18 + 5t-18\leqslant73 - 18$. This simplifies to $5t\leqslant55$.

Step3: Divide both sides by 5

Dividing both sides of the inequality $5t\leqslant55$ by 5 gives $t\leqslant11$.

Answer:

$t\leqslant11$