Question

a reaction of heating calcium carbonate produces calcium oxide and carbon dioxide gas. heat 10.0 g calcium carbonate until no more carbon dioxide gas is given off. the remaining material has a mass of 5.6 g. what mass of carbon dioxide gas was produced in the reaction? ____ g

Explanation:

Step1: Apply the law of conservation of mass

According to the law of conservation of mass, the mass of reactants equals the mass of products.
The mass of reactant (calcium carbonate) is $m_{reactant}=10.0\ g$.
The mass of one product (calcium oxide) is $m_{CaO} = 5.6\ g$. Let the mass of carbon dioxide be $m_{CO_2}$.
We know that $m_{reactant}=m_{CaO}+m_{CO_2}$.

Step2: Solve for the mass of carbon dioxide

Rearrange the formula to get $m_{CO_2}=m_{reactant}-m_{CaO}$.
Substitute the values: $m_{CO_2}=10.0\ g - 5.6\ g$.
Calculate: $m_{CO_2}=4.4\ g$.

Answer:

$4.4$