Question

is the reaction a double - displacement or single - replacement reaction? how do you determine whether the products formed are insoluble or soluble in water?
reactions involving ionic salt solutions
naoh(aq)+cuso₄(aq)
the chemicals turn into a mixture.
no observable change
bubbles formed in mixture
mixtures color changed
solid formed in mixture
test tube felt colder
test tube felt hotter
no reaction occurred
cu₂oh(s)
cu(oh)₂(aq)
cuoh(s)
cu(oh)₂(s)
na₂so₄(aq)
naso₄(aq)
naso₄(s)
nacl(aq)+pb(no₃)₂(aq)
the chemicals didnt really mix.
no observable change
bubbles formed in mixture
mixtures color changed
solid formed in mixture
test tube felt colder
test tube felt hotter
no reaction occurred
pbcl₂(aq)
pbcl₂(s)
pbcl(s)
pb₂cl(s)
nano₃(aq)
nano₃(s)
na₂no₃(aq)
na(no₃)₂(s)

Explanation:

Step1: Identify reaction type

Double - displacement reaction: ions exchange partners. For \(NaOH(aq)+CuSO_{4}(aq)\), \(Na^{+}\) and \(Cu^{2 +}\) exchange partners. For \(NaCl(aq)+Pb(NO_{3})_{2}(aq)\), \(Na^{+}\) and \(Pb^{2+}\) exchange partners.

Step2: Determine solubility

Use solubility rules. For \(Cu(OH)_{2}\): hydroxides of transition metals (like \(Cu\)) are generally insoluble. For \(Na_{2}SO_{4}\): salts with \(Na^{+}\) (Group 1 cation) are soluble. For \(PbCl_{2}\): chlorides of \(Pb^{2+}\) are insoluble. For \(NaNO_{3}\): nitrates (\(NO_{3}^{-}\)) are soluble.

Answer:

The reactions \(NaOH(aq)+CuSO_{4}(aq)\) and \(NaCl(aq)+Pb(NO_{3})_{2}(aq)\) are double - displacement reactions. To determine solubility, use solubility rules (e.g., Group 1 salts, nitrates are soluble; many transition - metal hydroxides, \(PbCl_{2}\) are insoluble).