Question

in the reaction _h₂ + n₂ → 2nh₃, what coefficient should be placed in front of h₂ to balance the reaction?
1
2
3
no coefficient is needed

Explanation:

Step1: Count hydrogen atoms on the right - hand side

In \(2NH_3\), the number of hydrogen atoms is \(2\times3 = 6\).

Step2: Determine the coefficient of \(H_2\)

Let the coefficient of \(H_2\) be \(x\). Since each \(H_2\) molecule has 2 hydrogen atoms, and the number of hydrogen atoms on the left - hand side should equal the number on the right - hand side. We have \(2x=6\), so \(x = 3\).

Answer:

3