d) $\text{koh} + \text{so}_3 \
ightarrow \text{k}_2\text{so}_4 + \text{h}_2\text{o}$

| reactants | products |
| :--- | :--- |
| | |

Question

d) $\text{koh} + \text{so}_3 \
ightarrow \text{k}_2\text{so}_4 + \text{h}_2\text{o}$

| reactants | products |
| :--- | :--- |
| | |

Accepted Answer

# Explanation:

🆕 New Concept Discovered: Balancing Chemical Equations
*Equalizing atoms on both sides of a reaction*

## Step 1: Count the atoms on each side

To balance the chemical equation, we first count the number of atoms of each element in the reactants (left side) and products (right side) of the unbalanced equation:

$$ \text{KOH} + \text{SO}_3
ightarrow \text{K}_2\text{SO}_4 + \text{H}_2\text{O} $$

* **Reactants:**
  * Potassium ($\text{K}$): $1$
  * Oxygen ($\text{O}$): $1 \text{ (from KOH)} + 3 \text{ (from SO}_3\text{)} = 4$
  * Hydrogen ($\text{H}$): $1$
  * Sulfur ($\text{S}$): $1$

* **Products:**
  * Potassium ($\text{K}$): $2$
  * Oxygen ($\text{O}$): $4 \text{ (from K}_2\text{SO}_4\text{)} + 1 \text{ (from H}_2\text{O)} = 5$
  * Hydrogen ($\text{H}$): $2$
  * Sulfur ($\text{S}$): $1$

## Step 2: Balance Potassium (K)

We have $2$ potassium atoms on the product side and only $1$ on the reactant side. To balance them, place a coefficient of $2$ in front of $\text{KOH}$ on the reactant side:

$$ 2\text{KOH} + \text{SO}_3
ightarrow \text{K}_2\text{SO}_4 + \text{H}_2\text{O} $$

## Step 3: Recount and verify all atoms

Now, let's recount the atoms with the new coefficient to see if the entire equation is balanced:

* **Reactants:**
  * Potassium ($\text{K}$): $2 \times 1 = 2$
  * Oxygen ($\text{O}$): $2 \times 1 \text{ (from 2KOH)} + 3 \text{ (from SO}_3\text{)} = 5$
  * Hydrogen ($\text{H}$): $2 \times 1 = 2$
  * Sulfur ($\text{S}$): $1$

* **Products:**
  * Potassium ($\text{K}$): $2$
  * Oxygen ($\text{O}$): $4 \text{ (from K}_2\text{SO}_4\text{)} + 1 \text{ (from H}_2\text{O)} = 5$
  * Hydrogen ($\text{H}$): $2$
  * Sulfur ($\text{S}$): $1$

All atoms are now equal on both sides.

# Answer:

### Balanced Equation:
$$ 2\text{KOH} + \text{SO}_3
ightarrow \text{K}_2\text{SO}_4 + \text{H}_2\text{O} $$

### Atom Inventory Table:

| Element | Reactants (Left Side) | Products (Right Side) |
| :--- | :--- | :--- |
| **Potassium (K)** | $2$ | $2$ |
| **Oxygen (O)** | $5$ | $5$ |
| **Hydrogen (H)** | $2$ | $2$ |
| **Sulfur (S)** | $1$ | $1$ |

Element	Reactants (Left Side)	Products (Right Side)
Oxygen (O)	\(5\)	\(5\)
Hydrogen (H)	\(2\)	\(2\)
Sulfur (S)	\(1\)	\(1\)

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Step 1: Count the atoms on each side

Step 2: Balance Potassium (K)

Step 3: Recount and verify all atoms

Answer:

Balanced Equation:

Atom Inventory Table: