Question

questions 21 - 23 prompt
questions 21 - 23: determine the molecular equation, type of reaction, and the net ionic equation for the following reactions.
molecular equation: $nh_4cl(aq)+naoh(aq)\to nh_4oh(s)+nacl(aq)$
type of reaction:
net ionic equatio

Explanation:

Step1: Analyze the reaction

In the reaction \(NH_4Cl(aq)+NaOH(aq)\to NH_4OH(s)+NaCl(aq)\), \(NH_4Cl\) is an acid - base salt (\(NH_4^+\) can act as a weak acid in some contexts, and \(NaOH\) is a strong base). But actually, \(NH_4OH\) is not a stable solid. The correct reaction is \(NH_4Cl(aq)+NaOH(aq)\to NH_3(g)+H_2O(l)+NaCl(aq)\) (because \(NH_4OH\) decomposes into \(NH_3\) and \(H_2O\)).

Step2: Determine the reaction type

Since a gas (\(NH_3\)) is produced, it is a gas - evolving reaction.

Step3: Write the net ionic equation

First, write the complete ionic equation: \(NH_4^+(aq)+Cl^-(aq)+Na^+(aq)+OH^-(aq)\to NH_3(g)+H_2O(l)+Na^+(aq)+Cl^-(aq)\)
Then, cancel out the spectator ions (\(Na^+\) and \(Cl^-\))
The net ionic equation is \(NH_4^+(aq)+OH^-(aq)\to NH_3(g)+H_2O(l)\)

Answer:

Type of reaction: gas - evolving reaction
Net ionic equation: \(NH_4^+(aq)+OH^-(aq)\to NH_3(g)+H_2O(l)\)