Question

question 3. which element in each pair is more electronegative?
a) as, k
b) n, sb
c) sr, be

Explanation:

To determine the more electronegative element in each pair, we use the trend of electronegativity in the periodic table: electronegativity generally increases across a period (from left to right) and decreases down a group (from top to bottom).

Part (a): As, K

• Step 1: Locate the elements on the periodic table

Arsenic (As) is in Group 15, Period 4. Potassium (K) is in Group 1, Period 4.

• Step 2: Apply the electronegativity trend

Across a period (from left to right), electronegativity increases. Since As is to the right of K in Period 4, As has a higher electronegativity.

Part (b): N, Sb

• Step 1: Locate the elements on the periodic table

Nitrogen (N) is in Group 15, Period 2. Antimony (Sb) is in Group 15, Period 5.

• Step 2: Apply the electronegativity trend

Down a group (from top to bottom), electronegativity decreases. Since N is above Sb in Group 15, N has a higher electronegativity.

Part (c): Sr, Be

• Step 1: Locate the elements on the periodic table

Strontium (Sr) is in Group 2, Period 5. Beryllium (Be) is in Group 2, Period 2.

• Step 2: Apply the electronegativity trend

Down a group (from top to bottom), electronegativity decreases. Since Be is above Sr in Group 2, Be has a higher electronegativity.

Answer:

a) As
b) N
c) Be