Question

question 1
what products will form when barium reacts with nitrogen?
○ ba₂n₃
○ nba₃
○ ban₃
○ ba₃n₂
○ ban

Explanation:

Step1: Determine oxidation states

Barium (Ba) is an alkaline earth metal, so it has an oxidation state of +2. Nitrogen (N) in binary ionic compounds with metals (like Ba) typically has an oxidation state of -3 (as part of the nitride ion, \( \text{N}^{3-} \)).

Step2: Use criss - cross method for formula

To form a neutral compound, the total positive charge from Ba ions and total negative charge from N ions must be equal. Let the formula be \( \text{Ba}_x\text{N}_y \). The charge of Ba is +2, so total positive charge is \( 2x \). The charge of N is -3, so total negative charge is \( 3y \). For neutrality, \( 2x = 3y \). The smallest whole - number solution for \( x \) and \( y \) is when \( x = 3 \) and \( y = 2 \) (since \( 2\times3=3\times2 = 6 \)). So the formula of barium nitride is \( \text{Ba}_3\text{N}_2 \).

Answer:

\( \text{Ba}_3\text{N}_2 \) (the option corresponding to \( \text{Ba}_3\text{N}_2 \))