Question

question 1
what is the oxidation state of sulfur in the sulfite ion?
○ 2-
○ 3+
○ 6+
○ 2+
○ 4+

Explanation:

Step1: Recall Sulfite Ion Formula

The sulfite ion is $\ce{SO_3^{2-}}$. Let the oxidation state of S be $x$. Oxygen (O) typically has an oxidation state of $-2$ (except in peroxides, etc.).

Step2: Set Up Oxidation State Equation

For a polyatomic ion, the sum of oxidation states equals the ion's charge. For $\ce{SO_3^{2-}}$:
$x + 3(-2) = -2$

Step3: Solve for $x$

Simplify the equation:
$x - 6 = -2$
Add 6 to both sides:
$x = -2 + 6 = +4$

Answer:

4+