Question

question 7
1 pts
when the reaction shown is correctly balanced, the coefficients are:
c₆h₁₄ (l) + o₂ (g) → co₂ (g) + h₂o (g)
2 12, 12, 14
1, 6, 6, 7
2, 16.5, 12, 7
2, 19, 12, 14
1, 3.5, 6, 7

Explanation:

Step1: Balance carbon atoms

Let the coefficient of \(C_6H_{14}\) be \(a\), \(CO_2\) be \(b\). For carbon balance: \(6a = b\).

Step2: Balance hydrogen atoms

Let the coefficient of \(C_6H_{14}\) be \(a\), \(H_2O\) be \(c\). For hydrogen balance: \(14a=2c\), so \(c = 7a\).

Step3: Balance oxygen atoms

Let the coefficient of \(C_6H_{14}\) be \(a\), \(O_2\) be \(d\), \(CO_2\) be \(b\), \(H_2O\) be \(c\). For oxygen balance: \(2d=2b + c\). Substitute \(b = 6a\) and \(c = 7a\) into \(2d=2b + c\), we get \(2d=2\times6a+7a=19a\).

If \(a = 2\), then \(b=12\), \(c = 14\), \(d = 19\)

Answer:

\(2,19,12,14\) (the fourth option)