Question

question 2
2 pts
what mass of sodium hydroxide will completely react with 3.612 mol of hcl?
naoh + hcl --> h₂o + nacl
3.612 g
0.09030 g
144.5 g
1107 g

Explanation:

Step1: Determine mole ratio

From the balanced equation \(NaOH + HCl
ightarrow H_2O+NaCl\), the mole ratio of \(NaOH\) to \(HCl\) is \(1:1\). So, \(n(NaOH)=n(HCl) = 3.612\space mol\)

Step2: Calculate molar mass of \(NaOH\)

The molar mass of \(NaOH\) is \(M = 22.99\space g/mol+16.00\space g/mol + 1.01\space g/mol=40.00\space g/mol\)

Step3: Calculate mass of \(NaOH\)

Using the formula \(m = n\times M\), we substitute \(n = 3.612\space mol\) and \(M=40.00\space g/mol\). So, \(m=3.612\space mol\times40.00\space g/mol = 144.48\space g\approx144.5\space g\)

Answer:

144.5 g (the third option)