Question

question 4 (5 points)
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suppose a phosphorous atom forms a bond with a fluorine atom. what type of bond must form between these two elements?
a) ionic bond
b) covalent bond
c) metallic bond
d) polar covalent bond

Explanation:

1. First, recall the types of bonds: Ionic bonds form between metals and non - metals (involving electron transfer), metallic bonds between metal atoms, and covalent bonds (including polar covalent) between non - metals.
2. Phosphorus (P) and fluorine (F) are both non - metals. So, they will not form ionic (A is wrong) or metallic (C is wrong) bonds.
3. Now, consider the electronegativity difference. Fluorine is the most electronegative element, and phosphorus has a significantly lower electronegativity. When two non - metals with a significant electronegativity difference bond, they form a polar covalent bond. A pure covalent bond (non - polar) occurs when electronegativity difference is zero or very small. Since P and F have a large electronegativity difference, the bond between them is a polar covalent bond. Option B is a general covalent bond, but the specific type here is polar covalent because of the electronegativity difference.

Answer:

D) Polar covalent bond