Question

question 1 (2 points)
answer each of the following as either true or false
1 an acid is a chemical that produces h⁺¹ or its hydrated form h₃o⁺¹ in water
2 an acid will have at least one h in the front of its formula
3 when an acid is put into water it makes the water act as a base
4 hcl + h₂o → cl⁻¹ + h₃o⁺¹
a. true b. false

Explanation:

1. By the definition of an acid (Arrhenius definition), an acid produces \(H^+\) (or \(H_3O^+\) when hydrated) in water. So this is true.
2. Some acids (like organic acids, e.g., acetic acid \(CH_3COOH\)) do not have \(H\) at the front of their formula in the way some inorganic acids do, but the general idea for many common acids (especially binary and oxyacids) has \(H\) at the front. However, strictly, there are exceptions, but the statement is a general rule for many acids. Wait, no—actually, for example, \(H_2SO_4\) has \(H\) at front, but \(CH_3COOH\) is written with \(H\) not at the very front in the condensed formula but still has acidic \(H\). Wait, the statement says "at least one \(H\) in the front of its formula". For example, \(HNO_3\) has \(H\) at front, \(HCl\) too. But for carboxylic acids, the formula is \(R - COOH\), so the \(H\) of the carboxyl group is not at the very front of the entire formula (the \(R\) group is in front). Wait, maybe the statement is intended to be about inorganic acids? But the question is a bit ambiguous. Wait, no—actually, the Arrhenius and Bronsted - Lowry definitions: an acid is a proton donor. The formula of an acid (especially binary acids like \(HCl\), \(HBr\), and oxyacids like \(H_2SO_4\)) have \(H\) at the front. But for organic acids, the formula is written with the alkyl group first. However, the statement says "will have at least one \(H\) in the front of its formula". So is this always true? Let's think: for \(HCl\), \(H\) is front; \(H_2SO_4\), \(H\) is front; \(CH_3COOH\) is written as \(CH_3COOH\), so the \(H\) of the \(COOH\) is not at the front of the entire formula (the \(CH_3\) is in front). So this statement is false. Wait, but maybe the question is considering only inorganic acids? No, the question is general. So the statement is false.
3. When an acid (proton donor) is added to water, water acts as a base (proton acceptor) because it accepts the proton from the acid to form \(H_3O^+\). So this is true.
4. \(HCl\) is a strong acid, so it dissociates completely in water. \(HCl\) donates a proton to \(H_2O\), forming \(Cl^-\) and \(H_3O^+\). So the reaction \(HCl + H_2O

ightarrow Cl^{-1}+H_3O^{+1}\) is correct. So this is true.

Answer:

1. A. true
2. B. false
3. A. true
4. A. true