Question

question 1 (1 point)
what is the net ionic equation for the reaction?
h₃po₄ + 3koh → k₃po₄ + 3h₂o
3k⁺ + 3oh⁻ → 3koh
po₄³⁻ + oh⁻ → h₃po₄
h⁺ + oh⁻ → h₂o
3h⁺ + 3k⁺ → 3kh
3k⁺ + po₄³⁻ → k₃po₄

Explanation:

Step1: Write the molecular equation

$$H_{3}PO_{4}+3KOH ightarrow K_{3}PO_{4}+3H_{2}O$$

Step2: Write the total ionic equation

$$3H^{+}+PO_{4}^{3 -}+3K^{+}+3OH^{-} ightarrow 3K^{+}+PO_{4}^{3 -}+3H_{2}O$$

Step3: Cancel out the spectator ions ($K^{+}$ and $PO_{4}^{3 -}$)

$$3H^{+}+3OH^{-} ightarrow 3H_{2}O$$

Divide both sides by 3:

$$H^{+}+OH^{-} ightarrow H_{2}O$$

Answer:

$H^{+}+OH^{-}
ightarrow H_{2}O$