Question

question 2 (1 point)
use le chateliers principle to answer the following:
n₂ + 3 h₂ ↔ 2 nh₃ + heat
the h₂ 1 when the n₂ is decreased
the h₂ 2 when the nh₃ is increased
the h₂ 3 when the n₂ is increased
the h₂ 4 when the temperature is decreased
a. increases b. decreases c. is unchanged

Explanation:

Step1: Analyze effect of decreasing [N₂]

Le Chatelier's Principle: If a reactant (N₂) is decreased, the equilibrium shifts left (reverse reaction favored) to produce more N₂. This means H₂ (also a reactant) is produced, so [H₂] increases. So for 1, answer is A.

Step2: Analyze effect of increasing [NH₃]

Increasing product (NH₃) shifts equilibrium left (reverse reaction: 2NH₃ → N₂ + 3H₂). So H₂ is produced, [H₂] increases. For 2, answer is A.

Step3: Analyze effect of increasing [N₂]

Increasing reactant (N₂) shifts equilibrium right (forward reaction: N₂ + 3H₂ → 2NH₃). H₂ is consumed, so [H₂] decreases. For 3, answer is B.

Step4: Analyze effect of decreasing temperature

The reaction is exothermic (releases heat, heat is a product). Decreasing temperature (removing heat) shifts equilibrium right (forward reaction favored) to produce heat. So H₂ is consumed, [H₂] decreases. For 4, answer is B.

Answer:

1. A. increases
2. A. increases
3. B. decreases
4. B. decreases