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question 5 (1 point) balance the reaction, do not leave any fractions, …

Question

question 5 (1 point)
balance the reaction, do not leave any fractions, dont leave anything blank, then answer the questions about the reaction
1 hg₃(po₃)₂ + 2 zn → 3 hg + 4 zn₃(po₃)₂
this is an 5 reaction.
is this a redox reaction? (yes/no)6, because hg⁺² is reduced to hg⁰, and because zn⁰ is 7 to zn⁺².
will the reaction happen as it is written? (yes/no)8, because the activity series tells us that hg is more 9 than zn. the reverse reaction would not happen.
a. 1 b. 2 c. 3 d. 4 e. 5 f. 6 g. 7 h. 8
i. 9 j. 10 k. 12 l. 14 m. 16 n. 18 o. 20 p. 21
q. 24 r. 26 s. 28 t. synthesis u. decomposition
v. single displacement w. double displacement x. neutralization
y. combustion z. yes aa. no bb. reactive cc. stable
dd. oxidized ee. reduced

Explanation:

Step1: Balance the chemical equation

Count the number of atoms of each element on both sides. For the phosphate - containing compound, we have \(Hg_3(PO_3)_2\) and \(Zn_3(PO_3)_2\).
Let's start by balancing the \(Zn\) and \(Hg\) atoms.
If we put a coefficient of \(1\) in front of \(Hg_3(PO_3)_2\), to balance the \(Hg\) atoms, we need a coefficient of \(3\) in front of \(Hg\).
To balance the \(Zn\) atoms, since we have \(Zn_3(PO_3)_2\), we need a coefficient of \(3\) in front of \(Zn\).
The balanced equation is \(Hg_3(PO_3)_2+3Zn
ightarrow3Hg + Zn_3(PO_3)_2\)

Step2: Identify the type of reaction

In a single - displacement reaction, the general form is \(A + BC
ightarrow AC+ B\). Here, \(Zn\) displaces \(Hg\) from \(Hg_3(PO_3)_2\), so it is a single - displacement reaction (\(V\))

Step3: Determine if it is a redox reaction

In a redox reaction, there is a transfer of electrons (change in oxidation states). \(Hg^{2 +}\) (in \(Hg_3(PO_3)_2\)) is reduced to \(Hg^0\) (in \(Hg\)), and \(Zn^0\) (in \(Zn\)) is oxidized (\(DD\)) to \(Zn^{2+}\) (in \(Zn_3(PO_3)_2\)). So it is a redox reaction (\(Z\))

Step4: Check if the reaction will occur based on the activity series

The activity series of metals: \(Zn\) is more reactive than \(Hg\). A more reactive metal can displace a less reactive metal from its compound. So the reaction \(Hg_3(PO_3)_2+3Zn
ightarrow3Hg + Zn_3(PO_3)_2\) will happen (\(Z\)), because \(Hg\) is less reactive (more stable (\(CC\))) than \(Zn\)

Answer:

  1. \(A\) (coefficient of \(Hg_3(PO_3)_2\) is \(1\))
  2. \(C\) (coefficient of \(Zn\) is \(3\))
  3. \(C\) (coefficient of \(Hg\) is \(3\))
  4. \(A\) (coefficient of \(Zn_3(PO_3)_2\) is \(1\))
  5. \(V\) (single - displacement reaction)
  6. \(Z\) (yes, it is a redox reaction)
  7. \(DD\) (oxidized)
  8. \(Z\) (yes, the reaction will happen)
  9. \(CC\) (stable)