Question

question 1 of 37
balance the following chemical equation (if necessary):
c₃h₆(g) + o₂(g) → co₂(g) + h₂o(g)

Explanation:

Step1: Balance carbon atoms

On the left - hand side, there are 3 carbon atoms in \(C_3H_6\). On the right - hand side, carbon is present in \(CO_2\). So, we put a coefficient of 3 in front of \(CO_2\).
\(C_3H_6(g)+O_2(g)\to3CO_2(g)+H_2O(g)\)

Step2: Balance hydrogen atoms

On the left - hand side, there are 6 hydrogen atoms in \(C_3H_6\). On the right - hand side, hydrogen is present in \(H_2O\). So, we put a coefficient of 3 in front of \(H_2O\).
\(C_3H_6(g)+O_2(g)\to3CO_2(g)+3H_2O(g)\)

Step3: Balance oxygen atoms

On the right - hand side, the number of oxygen atoms is \(3\times2 + 3\times1=9\). On the left - hand side, oxygen is present in \(O_2\). So, we put a coefficient of \(\frac{9}{2}\) in front of \(O_2\). But we usually prefer whole - number coefficients. Multiply the entire equation by 2 to get rid of the fraction.
\(2C_3H_6(g)+9O_2(g)\to6CO_2(g)+6H_2O(g)\)

Answer:

\(2C_3H_6(g)+9O_2(g)\to6CO_2(g)+6H_2O(g)\)