Question

question 33 (2 points)
give the complete electron configuration of titanium, ti, element 22. use the aufbau principle.
1s² 2s² 2p⁶ 3s² 1 2 3
a. 3s⁰ b. 3s¹ c. 3s² d. 3p⁰ e. 3p¹ f. 3p²
g. 3p³ h. 3p⁴ i. 3p⁵ j. 3p⁶ k. 3d⁰ l. 3d¹
m. 3d² n. 3d³ o. 3d⁴ p. 3d⁵ q. 3d⁶ r. 3d⁷
s. 3d⁸ t. 3d⁹ u. 3d¹⁰ v. 4s⁰ w. 4s¹ x. 4s²
y. 4p⁰ z. 4p¹ aa. 4p² bb. 4p³

Explanation:

Step1: Recall Aufbau principle

Electrons fill orbitals in order of increasing energy: 1s < 2s < 2p < 3s < 3p < 4s < 3d.

Step2: Determine remaining electrons

Titanium has 22 electrons. After filling 1s²2s²2p⁶3s², we have accounted for 2 + 2+6 + 2=12 electrons. So we have 22 - 12 = 10 electrons left to place.

Step3: Fill 3p orbital

The next - highest energy orbital is 3p, which can hold 6 electrons. So the next configuration is 3p⁶. Now we have 10 - 6 = 4 electrons left.

Step4: Fill 4s orbital

The 4s orbital is filled next and can hold 2 electrons. So the configuration becomes 4s². Now we have 4 - 2 = 2 electrons left.

Step5: Fill 3d orbital

The remaining 2 electrons go into the 3d orbital, giving 3d².

Answer:

1. J. 3p⁶
2. X. 4s²
3. M. 3d²