Question

question 2 of 25
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how many grams of oxygen are contained in 8.50 g of al₂(so₄)₃?
g o
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Explanation:

Step1: Calculate the molar mass of \(Al_2(SO_4)_3\)

The molar mass of \(Al\) is \(26.98\ g/mol\), \(S\) is \(32.07\ g/mol\), and \(O\) is \(16.00\ g/mol\).

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Step2: Determine the mass fraction of \(O\) in \(Al_2(SO_4)_3\)

There are \(12\) \(O\) atoms in \(Al_2(SO_4)_3\).
The mass of \(O\) in one mole of \(Al_2(SO_4)_3\) is \(12\times16.00 = 192.00\ g\).
The mass fraction of \(O\) is \(\frac{192.00}{342.17}\).

Step3: Calculate the mass of \(O\) in \(8.50\ g\) of \(Al_2(SO_4)_3\)

$$m_O=8.50\times\frac{192.00}{342.17}$$

$$m_O=\frac{1632}{342.17}\approx4.77\ g$$

Answer:

\(4.77\)