Question

question 23 (2 points)
name the organic product that is formed when 2 - methylpent - 1 - ene and hcl react.

Explanation:

Step1: Analyze the reaction mechanism

Alkenes react with HCl via an electrophilic addition mechanism. According to Markovnikov's rule, the hydrogen atom from HCl adds to the carbon atom of the double bond that has more hydrogen atoms attached to it.

Step2: Determine the product structure

For 2 - methylpent - 1 - ene (\(CH_2 = C(CH_3)CH_2CH_2CH_3\)), the hydrogen from HCl adds to the \(CH_2\) carbon (since it has more H atoms compared to the \(C(CH_3)\) carbon of the double bond). The Cl atom then adds to the \(C(CH_3)\) carbon. The resulting structure is \(CH_3C(Cl)(CH_3)CH_2CH_2CH_3\).

Step3: Name the product

Using IUPAC naming rules for alkyl halides:

• The parent chain is pentane (5 - carbon chain).
• There is a methyl group at the 2 - position and a chloro group at the 2 - position.

So the name is 2 - chloro - 2 - methylpentane.

Answer:

2 - chloro - 2 - methylpentane