Question

question 15
1 pts
the reaction between strontium hydroxide and chloric acid produces

two ionic compounds

an ionic compound

a molecular compound and an ionic compound

a molecular compounds

two molecular compounds

question 16
1 pts
in which reaction are electrons transfered from one species to another?

2na (s) + 2h2o (l) → 2naoh (aq) + h2 (g)

2 al(oh)3 (aq) + 3 h2so4 (aq) → al2(so4)3 (s) + 6 h2o (l)

2 agno3 (aq) + k2so4 (aq) → 2 kno3 (aq) + ag2so4 (s)

3 ca(no3)2 (aq) + 2 na3po4 (aq) → ca3(po4)2 (s) + 6 nano3 (aq).

hcl (aq) + naoh (aq) → nacl (aq) + h2o (l)

Explanation:

Question 15

Strontium hydroxide (\(Sr(OH)_2\)) is a strong base and chloric acid (\(HClO_3\)) is a strong acid. Their reaction is a neutralization reaction: \(Sr(OH)_2 + 2HClO_3=Sr(ClO_3)_2 + 2H_2O\). \(Sr(ClO_3)_2\) is an ionic compound (composed of \(Sr^{2 +}\) and \(ClO_3^{-}\) ions), and \(H_2O\) is a molecular compound (formed by covalent bonds between \(H\) and \(O\) atoms).

• For \(2Na(s)+2H_2O(l)\to2NaOH(aq) + H_2(g)\):
• Sodium (\(Na\)) goes from an oxidation state of \(0\) (in \(Na(s)\)) to \(+ 1\) (in \(NaOH\)), so it is oxidized (loses electrons).
• Hydrogen in \(H_2O\) goes from an oxidation state of \(+1\) to \(0\) (in \(H_2\)), so it is reduced (gains electrons). Electrons are transferred from \(Na\) to \(H\) in \(H_2O\).
• For \(2Al(OH)_3(aq)+3H_2SO_4(aq)\to Al_2(SO_4)_3(s)+6H_2O(l)\): This is a neutralization (double - displacement) reaction. There is no change in oxidation states of the elements (\(Al: + 3\), \(S:+6\), \(O:-2\), \(H:+1\) throughout the reaction).
• For \(2AgNO_3(aq)+K_2SO_4(aq)\to2KNO_3(aq)+Ag_2SO_4(s)\): This is a double - displacement reaction. Oxidation states (\(Ag:+1\), \(N:+5\), \(O:-2\), \(K:+1\), \(S:+6\)) remain the same.
• For \(3Ca(NO_3)_2(aq)+2Na_3PO_4(aq)\to Ca_3(PO_4)_2(s)+6NaNO_3(aq)\): This is a double - displacement reaction. Oxidation states (\(Ca:+2\), \(N:+5\), \(O:-2\), \(Na:+1\), \(P:+5\)) remain unchanged.
• For \(HCl(aq)+NaOH(aq)\to NaCl(aq)+H_2O(l)\): This is a neutralization (double - displacement) reaction. Oxidation states (\(H:+1\), \(Cl:-1\), \(Na:+1\), \(O:-2\)) remain the same.

Answer:

a molecular compound and an ionic compound

Question 16