Question

question 15 (1 point)
which subshell contains only one orbital?
4d
6f
3d
2s
1p

Explanation:

• The number of orbitals in a subshell is determined by the magnetic quantum number \(m_l\).
• For an \(s\) subshell (\(l = 0\)), \(m_l=0\) (only one value). So, an \(s\) subshell has 1 orbital.
• For a \(p\) subshell (\(l = 1\)), \(m_l=- 1,0, + 1\) (three values), so it has 3 orbitals.
• For a \(d\) subshell (\(l = 2\)), \(m_l=-2,-1,0, + 1,+2\) (five values), so it has 5 orbitals.
• For an \(f\) subshell (\(l = 3\)), \(m_l=-3,-2,-1,0, + 1,+2,+3\) (seven values), so it has 7 orbitals.
• \(4d\) is a \(d\) subshell (\(l = 2\)), \(6f\) is an \(f\) subshell (\(l = 3\)), \(3d\) is a \(d\) subshell (\(l = 2\)), \(2s\) is an \(s\) subshell (\(l = 0\)), and \(1p\) does not exist (when \(n = 1\), \(l\) can only be \(0\)).

Answer:

\(2s\)