Question

qa 37 disscloss
drag and drop the correct answer choice to each answer blank. or, touch the answer choice followed by the answer blank.
this balanced equation represents the reaction of zn and pb(no₃)₂.
zn + pb(no₃)₂ → zn(no₃)₂ + pb
when 34 g of zn reacts with 27 g of pb(no₃)₂, 12 g of pb is produced. how many grams of zn(no₃)₂ are produced?
move the correct numerical answer to the first box, and the correct unit to the second box.
27 39 49 ml g g/ml

Explanation:

Step1: Apply the law of conservation of mass

The total mass of reactants should equal the total mass of products. The mass of reactants is the sum of the mass of Zn and \( \text{Pb(NO}_3\text{)}_2 \), so \( 34\,\text{g} + 27\,\text{g}=61\,\text{g} \).

Step2: Calculate the mass of \( \text{Zn(NO}_3\text{)}_2 \)

Let the mass of \( \text{Zn(NO}_3\text{)}_2 \) be \( m \). The total mass of products is the sum of the mass of Pb and \( \text{Zn(NO}_3\text{)}_2 \), so \( 61\,\text{g}=12\,\text{g}+m \). Solving for \( m \), we get \( m = 61\,\text{g}- 12\,\text{g}=49\,\text{g} \). The unit for mass is grams (g).

Answer:

49, g