Question

q13. (7 points)
(a) add the coefficients to balance the following chemical equation (doing a tally will be helpful):
1 c₃h₈(g) + 5 o₂(g) → 3 co₂(g) + 4 h₂o(l)
(b) how many moles of carbon dioxide are produced for every 24.3 moles of propane fuel (c₃h₈) burned? 72.9 mol

Explanation:

Step1: Identify mole - ratio from balanced equation

From the balanced equation $C_3H_8(g)+5O_2(g)
ightarrow3CO_2(g) + 4H_2O(l)$, the mole - ratio of $C_3H_8$ to $CO_2$ is $1:3$.

Step2: Set up proportion

Let $x$ be the number of moles of $CO_2$ produced. We have the proportion $\frac{1\ mol\ C_3H_8}{3\ mol\ CO_2}=\frac{24.3\ mol\ C_3H_8}{x}$.

Step3: Solve for $x$

Cross - multiply: $1\times x = 3\times24.3$. So $x=72.9$ mol.

Answer:

$72.9$ mol