Question

1. put the following in order from least to most electronegative. explain why you chose that order. beryllium, boron, carbon, fluorine, nitrogen 3. is chlorine or iodine more electronegative? explain why. 4. put the following in order from highest to lowest first ionization energy. explain why you chose that order. barium, beryllium, calcium, magnesium, radium 5. does magnesium or sulfur have a lower first ionization energy? explain 6. would tin or iodine be the best conductor of electricity? explain why. 7. would carbon or lead be a worse conductor of heat? explain why.

Explanation:

1. Electronegativity increases across a period. Beryllium (Be) is in group 2, boron (B) group 13, carbon (C) group 14, nitrogen (N) group 15, fluorine (F) group 17. So the order is Be < B < C < N < F.
2. Chlorine (Cl) is more electronegative than iodine (I). Electronegativity decreases down a group as atomic size increases, reducing the pull on electrons.
3. First ionization energy decreases down a group. Beryllium (Be) is highest (group 2, period 2), then magnesium (Mg) (group 2, period 3), calcium (Ca) (group 2, period 4), barium (Ba) (group 2, period 6), radium (Ra) (group 2, period 7). So order is Be > Mg > Ca > Ba > Ra.
4. Magnesium (Mg) has a lower first ionization energy than sulfur (S). Mg is in group 2 (losing 2 electrons easily), S is in group 16 (more electrons, higher nuclear charge).
5. Tin (Sn) is a metal (good conductor), iodine (I) is a non - metal (poor conductor). So tin is the better conductor.
6. Carbon (C) (e.g., diamond is a poor conductor, graphite has some conductivity but not as good as metals) is a worse conductor than lead (Pb) (a metal).

Answer:

1. Beryllium < Boron < Carbon < Nitrogen < Fluorine.
2. Chlorine is more electronegative.
3. Beryllium > Magnesium > Calcium > Barium > Radium.
4. Magnesium has a lower first ionization energy.
5. Tin is the better conductor.
6. Carbon is a worse conductor.