3. provide the formula for each of the following compounds.
a. sodium carbonate
g. nickel (ii) chloride
b. dinitrogen pentafluoride
h. iron (iii) sulfide
c. magnesium nitrate
i. potassium nitrite
d. cesium sulfide
j. calcium carbonate
e. di sulfur hexachloride
k. chromium (vi) phosphate
f. calcium oxalate
l. tin (ii) nitrite

Question

Accepted Answer

### Part c: Magnesium nitrate
# Explanation:
## Step1: Identify ions and charges
Magnesium ion is $Mg^{2+}$, nitrate ion is $NO_3^-$.
## Step2: Balance charges
To balance $2+$ and $1-$, we need 2 nitrate ions. So formula is $Mg(NO_3)_2$.
# Answer: $Mg(NO_3)_2$

### Part d: Cesium sulfide
# Explanation:
## Step1: Identify ions and charges
Cesium ion is $Cs^+$, sulfide ion is $S^{2-}$.
## Step2: Balance charges
To balance $1+$ and $2-$, we need 2 cesium ions. So formula is $Cs_2S$.
# Answer: $Cs_2S$

### Part e: Disulfur hexachloride
# Explanation:
## Step1: Use prefixes
"Di-" means 2 for sulfur, "hexa-" means 6 for chlorine.
## Step2: Write formula
So formula is $S_2Cl_6$.
# Answer: $S_2Cl_6$

### Part f: Calcium oxalate
# Explanation:
## Step1: Identify ions and charges
Calcium ion is $Ca^{2+}$, oxalate ion is $C_2O_4^{2-}$.
## Step2: Balance charges
Charges are equal (2+ and 2-), so 1:1 ratio. Formula is $CaC_2O_4$.
# Answer: $CaC_2O_4$

### Part i: Potassium nitrite
# Explanation:
## Step1: Identify ions and charges
Potassium ion is $K^+$, nitrite ion is $NO_2^-$.
## Step2: Balance charges
1+ and 1- balance, so formula is $KNO_2$.
# Answer: $KNO_2$

### Part j: Calcium carbonate
# Explanation:
## Step1: Identify ions and charges
Calcium ion is $Ca^{2+}$, carbonate ion is $CO_3^{2-}$.
## Step2: Balance charges
Charges are equal (2+ and 2-), so 1:1 ratio. Formula is $CaCO_3$.
# Answer: $CaCO_3$

### Part k: Chromium (VI) phosphate
# Explanation:
## Step1: Identify ions and charges
Chromium (VI) ion is $Cr^{6+}$, phosphate ion is $PO_4^{3-}$.
## Step2: Balance charges
Find least common multiple of 6 and 3, which is 6. So 1 $Cr^{6+}$ and 2 $PO_4^{3-}$ (since 2×3=6). Formula is $Cr(PO_4)_2$.
# Answer: $Cr(PO_4)_2$

### Part l: Tin (II) nitrite
# Explanation:
## Step1: Identify ions and charges
Tin (II) ion is $Sn^{2+}$, nitrite ion is $NO_2^-$.
## Step2: Balance charges
To balance 2+ and 1-, we need 2 nitrite ions. Formula is $Sn(NO_2)_2$.
# Answer: $Sn(NO_2)_2$

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QUESTION IMAGE

Question

Explanation:

Part c: Magnesium nitrate

Step1: Identify ions and charges

Step2: Balance charges

Step1: Identify ions and charges

Step2: Balance charges

Step1: Use prefixes

Step2: Write formula

Answer:

Part d: Cesium sulfide