Question

the pressure in a different 20.00 l container is 3.000 atm. it contains 33.3% o₂ and the rest is n₂. what is the partial pressure of each gas? the total pressure is 1 made up of 2 % o₂ and 3 % n₂. 33.3 percent means parts per hundred, so 33.3% = ------- 100 4 po₂ = -------(5 atm) = 6 atm 100 7 pn₂ = --------(8 atm) = 9 atm 100 a. 2.00 b. 1.00 c. 33.3 d. 66.7 e. 20.00 f. 3.00 g. 100

Explanation:

Step1: Determine the total pressure

The total pressure is given as \(3.000\) atm. So, blank 1 is \(F\) (since \(3.00\) is the value closest to \(3.000\) among the options).

Step2: Determine the percentage of \(N_2\)

If \(O_2\) is \(33.3\%\), then \(N_2\) is \(100 - 33.3=66.7\%\). So, blank 3 is \(D\).

Step3: Calculate the partial pressure of \(O_2\)

The formula for partial pressure \(P_i=\frac{\text{Percentage of }i}{100}\times P_{total}\). For \(O_2\), \(P_{O_2}=\frac{33.3}{100}\times3.00\) atm. So, blank 4 is \(C\), blank 5 is \(F\), and \(P_{O_2}=\frac{33.3}{100}\times3.00 = 1.00\) atm (blank 6 is \(B\)).

Step4: Calculate the partial pressure of \(N_2\)

For \(N_2\), \(P_{N_2}=\frac{66.7}{100}\times3.00\) atm. So, blank 7 is \(D\), blank 8 is \(F\), and \(P_{N_2}=\frac{66.7}{100}\times3.00=2.00\) atm (blank 9 is \(A\)).

Answer:

1. \(F. 3.00\)
2. \(C. 33.3\)
3. \(D. 66.7\)
4. \(C. 33.3\)
5. \(F. 3.00\)
6. \(B. 1.00\)
7. \(D. 66.7\)
8. \(F. 3.00\)
9. \(A. 2.00\)