pick the larger species from each pair.
match the words in the left column to the appropriate blanks in the sentences on the right.
reset
ba
when comparing the two species p and p³⁻ the larger of the two is
p³⁻
when comparing the two species ba and ba²⁺ the larger of the two is
ni²⁺
when comparing the two species ni and ni²⁺ the larger of the two is
ba²⁺
p
when comparing the two species s²⁻ and ca²⁺ the larger of the two is
ca²⁺
s²⁻
ni

Question

Accepted Answer

# Brief Explanations:
- **For $P$ and $P^{3 -}$**: Anions ($P^{3 -}$) are larger than their parent atoms ($P$). When a neutral atom gains electrons (to form an anion), electron - electron repulsions increase, and the electron cloud expands.
- **For $Ba$ and $Ba^{2+}$**: Cations ($Ba^{2+}$) are smaller than their parent atoms ($Ba$). When a neutral atom loses electrons (to form a cation), the effective nuclear charge acting on the remaining electrons increases, pulling the electrons closer to the nucleus.
- **For $Ni$ and $Ni^{2+}$**: Similar to the $Ba$ - $Ba^{2+}$ case. Cations ($Ni^{2+}$) are smaller than their parent atoms ($Ni$) because of the increased effective nuclear charge on the remaining electrons after electron loss.
- **For $S^{2 -}$ and $Ca^{2+}$**: Both $S^{2 -}$ and $Ca^{2+}$ are isoelectronic (have the same number of electrons). For isoelectronic species, the ion with the smaller nuclear charge has a larger radius. The nuclear charge of $S^{2 -}$ is $Z = 16$ and for $Ca^{2+}$ is $Z=20$. So, $S^{2 -}$ has a larger radius.

# Answer:
When comparing the two species $P$ and $P^{3 -}$ the larger of the two is $P^{3 -}$.
When comparing the two species $Ba$ and $Ba^{2+}$ the larger of the two is $Ba$.
When comparing the two species $Ni$ and $Ni^{2+}$ the larger of the two is $Ni$.
When comparing the two species $S^{2 -}$ and $Ca^{2+}$ the larger of the two is $S^{2 -}$.

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