Question

pb
express your answer in condensed form in order of increasing orbital energy as a string without blank space between orbitals. for example, he2s²2p² should be entered as he2s^22p^2.

Explanation:

Step1: Determine the noble gas core

Lead (Pb) has an atomic number of 82. The noble gas before Pb is xenon (Xe) with an atomic number of 54.

Step2: Write the remaining electron configuration

After [Xe], we have \(82 - 54=28\) electrons left. The electron configuration after [Xe] is \(6s^{2}4f^{14}5d^{10}6p^{2}\)

Answer:

[Xe]6s^24f^145d^106p^2