Question

part a
write a formula for the compound that forms between ca and cl.
cacl
ca₂cl₂
cacl₂
ca₂cl

Explanation:

Step1: Determine the charges of ions

Calcium (\(Ca\)) has a charge of \(+2\) (\(Ca^{2+}\)), and chlorine (\(Cl\)) has a charge of \(-1\) (\(Cl^{-}\)).

Step2: Balance the charges

To balance the charges, we need \(2\) \(Cl^{-}\) ions for every \(1\) \(Ca^{2+}\) ion.

Answer:

\(CaCl_{2}\) (the third option)