Question

part 1 of 2

when lead(ii) nitrate solution is added to sodium iodide solution, solid lead(ii) iodide forms and sodium nitrate solution remains. be sure to include the state of each reactant and product in the equation.

part 2 of 2

liquid disilicon hexachloride reacts with water to form solid silicon dioxide, hydrogen chloride gas, and hydrogen gas. be sure to include the state of each reactant and product in the equation.

Explanation:

Write formulas for Part 1

Using the Chemical Equation Balancing knowledge point
Reactants:

• Lead(II) nitrate solution: \(\text{Pb(NO}_3)_2(aq)\)
• Sodium iodide solution: \(\text{NaI}(aq)\)

Products:

• Solid lead(II) iodide: \(\text{PbI}_2(s)\)
• Sodium nitrate solution: \(\text{NaNO}_3(aq)\)

Balance equation for Part 1

Using the Chemical Equation Balancing knowledge point

$$ \text{Pb(NO}_3)_2(aq) + 2\text{NaI}(aq) ightarrow \text{PbI}_2(s) + 2\text{NaNO}_3(aq) $$

Write formulas for Part 2

Using the Chemical Equation Balancing knowledge point
Reactants:

• Liquid disilicon hexachloride: \(\text{Si}_2\text{Cl}_6(l)\)
• Water: \(\text{H}_2\text{O}(l)\)

Products:

• Solid silicon dioxide: \(\text{SiO}_2(s)\)
• Hydrogen chloride gas: \(\text{HCl}(g)\)
• Hydrogen gas: \(\text{H}_2(g)\)

Balance equation for Part 2

Using the Chemical Equation Balancing knowledge point

$$ \text{Si}_2\text{Cl}_6(l) + 4\text{H}_2\text{O}(l) ightarrow 2\text{SiO}_2(s) + 6\text{HCl}(g) + \text{H}_2(g) $$

Answer:

Question 1

$$\text{Pb(NO}_3)_2(aq) + 2\text{NaI}(aq) ightarrow \text{PbI}_2(s) + 2\text{NaNO}_3(aq)$$

Question 2

$$\text{Si}_2\text{Cl}_6(l) + 4\text{H}_2\text{O}(l) ightarrow 2\text{SiO}_2(s) + 6\text{HCl}(g) + \text{H}_2(g)$$