Question

part b fe(oh)3 spell out the full name of the compound. submit previous answers request answer x incorrect; try again; one attempt remaining since the compound overall is charge neutral, the sum of the charges of the hydroxide ions should be equal in magni of the iron cation. part c cu(no2)2 spell out the full name of the compound. submit previous answers request answer x incorrect; try again; 2 attempts remaining count the number of oxygen atoms in the polyatomic ion no2 and compare the ending of the name to other polyatomic

Explanation:

Part B

Step1: Analyze the ions

The compound \(Fe(OH)_3\) consists of iron (\(Fe\)) cation and hydroxide (\(OH^-\)) anion. The hydroxide ion has a charge of \(- 1\). Since there are three hydroxide ions (\(3\times(-1)=-3\)), the iron cation must have a charge of \(+3\) to make the compound neutral.

Step2: Name the compound

For ionic compounds with transition metals (iron is a transition metal), we use Roman numerals to indicate the charge of the metal cation. The name of the anion (\(OH^-\)) is hydroxide. So the name is iron(III) hydroxide.

Part C

Step1: Analyze the ions

The compound \(Cu(NO_2)_2\) consists of copper (\(Cu\)) cation and nitrite (\(NO_2^-\)) anion. The nitrite ion has a charge of \(-1\). Since there are two nitrite ions (\(2\times(-1)=-2\)), the copper cation must have a charge of \(+2\) to make the compound neutral.

Step2: Name the compound

For ionic compounds with transition metals (copper is a transition metal), we use Roman numerals to indicate the charge of the metal cation. The name of the anion (\(NO_2^-\)) is nitrite. So the name is copper(II) nitrite.

Answer:

• Part B: iron(III) hydroxide
• Part C: copper(II) nitrite