Question

the number of carbon atoms in 0.050 mol of c₁₂h₂₂o₁₁ (sucrose) is
12 c atoms
3.0 × 10²² c atoms
3.6 × 10²³ c atoms
3.3 × 10²³ c atoms

Explanation:

Step1: Determine moles of C

In 1 mol of \( C_{12}H_{22}O_{11} \), there are 12 mol of C. So for 0.050 mol of \( C_{12}H_{22}O_{11} \), moles of C = \( 0.050 \, \text{mol} \times 12 = 0.60 \, \text{mol} \) of C.

Step2: Calculate number of atoms

Using Avogadro's number (\( N_A = 6.022 \times 10^{23} \, \text{atoms/mol} \)), number of C atoms = \( 0.60 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \approx 3.6 \times 10^{23} \) atoms.

Answer:

\( 3.6 \times 10^{23} \, C \) atoms (the option: \( 3.6 \times 10^{23} \, C \) atoms)