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name write the electron configuration for each element below. draw arro…

Question

name
write the electron configuration for each element below. draw arrows within the orbital boxes to represent electron pairs
1.potassium (k) :

  1. carbon (c) :
  2. titanium (ti):

4.argon (ar) :

  1. sulfur (s) :

Explanation:

1. Potassium (K)

Step1: Determine atomic number

Potassium has atomic number 19, so 19 electrons.

Step2: Apply Aufbau principle

Fill orbitals in order \(1s, 2s, 2p, 3s, 3p, 4s, 3d, \dots\).
\(1s\) holds 2: \(1s^2\); \(2s\) holds 2: \(2s^2\); \(2p\) holds 6: \(2p^6\); \(3s\) holds 2: \(3s^2\); \(3p\) holds 6: \(3p^6\); remaining \(19 - (2 + 2 + 6 + 2 + 6) = 1\) electron in \(4s\): \(4s^1\).
So electron configuration: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^1\).

2. Carbon (C)

Step1: Atomic number

Carbon has atomic number 6, 6 electrons.

Step2: Aufbau principle

\(1s\) (2): \(1s^2\); \(2s\) (2): \(2s^2\); remaining \(6 - (2 + 2) = 2\) electrons in \(2p\): \(2p^2\).
Electron configuration: \(1s^2 2s^2 2p^2\).

3. Titanium (Ti)

Step1: Atomic number

Titanium has atomic number 22, 22 electrons.

Step2: Aufbau principle

\(1s^2\) (2); \(2s^2\) (2); \(2p^6\) (6); \(3s^2\) (2); \(3p^6\) (6); \(4s^2\) (2); remaining \(22 - (2 + 2 + 6 + 2 + 6 + 2) = 2\) electrons in \(3d\): \(3d^2\).
Electron configuration: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2\) (or \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^2 4s^2\) – note \(4s\) fills before \(3d\) but is often written with \(3d\) after for transition metals, though Aufbau order is \(4s\) first).

4. Argon (Ar)

Answer:

s:

  1. Potassium (K): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^1\)
  2. Carbon (C): \(1s^2 2s^2 2p^2\)
  3. Titanium (Ti): \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^2\) (or \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^2 4s^2\))
  4. Argon (Ar): \(1s^2 2s^2 2p^6 3s^2 3p^6\)
  5. Sulfur (S): \(1s^2 2s^2 2p^6 3s^2 3p^4\)