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texas chemistry teks 13a - 13d exam
- which statement best illustrates the first law of thermodynamics as described in teks 13a?
a. heat will spontaneously flow from a colder body to a warmer body.
b. energy cannot be created or destroyed, only converted from one form to another.
c. a system at absolute zero has no entropy.
d. when two systems are each in equilibrium with a third, they are in equilibrium with each other.
- which of the following everyday examples best illustrates the second law of thermodynamics (teks 13a)?
a. a hot cup of coffee left in a room eventually cools to room temperature.
b. ice forms spontaneously in a warm room.
c. a billiard ball rolling across a table loses speed due to friction.
d. a battery converts chemical energy into electrical energy without loss.
- the standard states (teks 13b) that students should \investigate the process of heat transfer using calorimetry.\ which experiment would most directly address this expectation?
a. measuring the volume of a gas at constant temperature.
b. mixing a hot acid and a base, measuring the temperature change of water.
c. using a spectrophotometer to measure absorbance of a dye solution.
d. observing the decay of a radioactive isotope over time.
- in a calorimetry experiment, 50 g of water at 22.0°c receives 4200 j of heat energy. what is the final temperature of the water? (assume specific heat of water = 4.20 j/g°c)
a. 38.0°c
b. 42.0°c
c. 22.8°c
d. 42.5°c
Step1: Use the heat formula
The formula for heat \(Q = mc\Delta T\), where \(Q\) is heat energy, \(m\) is mass, \(c\) is specific heat capacity, and \(\Delta T=T_{final}-T_{initial}\).
We know \(Q = 4200\space J\), \(m = 50\space g\), \(c=4.20\space J/g^{\circ}C\), \(T_{initial}=22.0^{\circ}C\).
Substitute into the formula: \(4200=50\times4.20\times(T_{final} - 22.0)\)
Step2: Solve for \(\Delta T\)
First, simplify the right - hand side: \(50\times4.20 = 210\).
The equation becomes \(4200=210\times(T_{final}- 22.0)\).
Then, \(\frac{4200}{210}=T_{final}-22.0\).
\(20=T_{final}-22.0\)
Step3: Solve for \(T_{final}\)
\(T_{final}=20 + 22.0=42.0^{\circ}C\)
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B. \(42.0^{\circ}C\)