name:
date:
naming lonic and polyatomic compounds worksheet
part i: directions: watch the edpuzzle first posted on canvas before answering this worksheet. for this worksheet, refer to the polyatomic list posted also on canvas.
write the name of each compound below.
remember:
• for lonic compounds, name the metal (cation) first, then the nonmetal (anion) and change its ending to -ide.
• for polyatomic compounds, use the polyatomic ions name directly (do not change endings).
• for transition metals with variable charges, include the roman numeral (e.g., fecl₂ = iron(ii) chloride).
• part ii: simple lonic compounds

part iii: polyatomic lonic compounds

Question

name:
date:
naming lonic and polyatomic compounds worksheet
part i: directions: watch the edpuzzle first posted on canvas before answering this worksheet. for this worksheet, refer to the polyatomic list posted also on canvas.
write the name of each compound below.
remember:
• for lonic compounds, name the metal (cation) first, then the nonmetal (anion) and change its ending to -ide.
• for polyatomic compounds, use the polyatomic ions name directly (do not change endings).
• for transition metals with variable charges, include the roman numeral (e.g., fecl₂ = iron(ii) chloride).
• part ii: simple lonic compounds

part iii: polyatomic lonic compounds

Accepted Answer

# Explanation:
## Step1: Name simple ionic compounds
For $NaCl$, the metal is sodium ($Na$) and the non - metal is chlorine ($Cl$). Using the rule for ionic compounds (metal first, non - metal with ending change), it is sodium chloride.
For $MgO$, the metal is magnesium ($Mg$) and the non - metal is oxygen ($O$). So it is magnesium oxide.
For $CaBr_{2}$, the metal is calcium ($Ca$) and the non - metal is bromine ($Br$). It is calcium bromide.
For $Al_{2}O_{3}$, the metal is aluminium ($Al$) and the non - metal is oxygen ($O$). It is aluminium oxide.
For $Li_{2}S$, the metal is lithium ($Li$) and the non - metal is sulfur ($S$). It is lithium sulfide.
For $K_{3}N$, the metal is potassium ($K$) and the non - metal is nitrogen ($N$). It is potassium nitride.
For $BaF_{2}$, the metal is barium ($Ba$) and the non - metal is fluorine ($F$). It is barium fluoride.
For $FeCl_{3}$, iron ($Fe$) is a transition metal. Chlorine has a charge of $- 1$. Let the charge of $Fe$ be $x$. In $FeCl_{3}$, using the charge balance $x+3\times(-1)=0$, so $x = + 3$. It is iron(III) chloride.
For $Cu_{2}O$, copper ($Cu$) is a transition metal. Oxygen has a charge of $-2$. Let the charge of $Cu$ be $y$. In $Cu_{2}O$, $2y+(-2)=0$, so $y = + 1$. It is copper(I) oxide.
For $SnO_{2}$, tin ($Sn$) is a transition metal. Oxygen has a charge of $-2$. Let the charge of $Sn$ be $z$. In $SnO_{2}$, $z + 2\times(-2)=0$, so $z=+4$. It is tin(IV) oxide.

## Step2: Name polyatomic ionic compounds
For $NaNO_{3}$, $Na$ is sodium and $NO_{3}^{-}$ is the nitrate ion. So it is sodium nitrate.
For $CaCO_{3}$, $Ca$ is calcium and $CO_{3}^{2 - }$ is the carbonate ion. So it is calcium carbonate.
For $KOH$, $K$ is potassium and $OH^{-}$ is the hydroxide ion. So it is potassium hydroxide.

# Answer:
1. Sodium chloride
2. Magnesium oxide
3. Calcium bromide
4. Aluminium oxide
5. Lithium sulfide
6. Potassium nitride
7. Barium fluoride
8. Iron(III) chloride
9. Copper(I) oxide
10. Tin(IV) oxide
11. Sodium nitrate
12. Calcium carbonate
13. Potassium hydroxide

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Step1: Name simple ionic compounds

Step2: Name polyatomic ionic compounds

Answer: