Question

3 nacl
c₆h₁₂o₆
2 caco₃
8 h₂o
chemical
formula
8
2
1
3
number of
compounds
na=
cl=
c=
h=
o=
ca=
c=
o=
h=
o=
total number of atoms
multiply the coefficient by the subscript

Explanation:

Step1: Calculate for \(3NaCl\)

For \(Na\): coefficient \(3\), sub - script \(1\) (since \(NaCl\) has one \(Na\)), so \(3\times1 = 3\).
For \(Cl\): coefficient \(3\), sub - script \(1\) (since \(NaCl\) has one \(Cl\)), so \(3\times1=3\).

Step2: Calculate for \(C_{6}H_{12}O_{6}\)

For \(C\): coefficient \(2\), sub - script \(6\), so \(2\times6 = 12\).
For \(H\): coefficient \(2\), sub - script \(12\), so \(2\times12 = 24\).
For \(O\): coefficient \(2\), sub - script \(6\), so \(2\times6=12\).

Step3: Calculate for \(2CaCO_{3}\)

For \(Ca\): coefficient \(2\), sub - script \(1\) (since \(CaCO_{3}\) has one \(Ca\)), so \(2\times1 = 2\).
For \(C\): coefficient \(2\), sub - script \(1\) (since \(CaCO_{3}\) has one \(C\)), so \(2\times1=2\).
For \(O\): coefficient \(2\), sub - script \(3\) (since \(CaCO_{3}\) has three \(O\)s), so \(2\times3 = 6\).

Step4: Calculate for \(8H_{2}O\)

For \(H\): coefficient \(8\), sub - script \(2\), so \(8\times2=16\).
For \(O\): coefficient \(8\), sub - script \(1\) (since \(H_{2}O\) has one \(O\)), so \(8\times1 = 8\).

Answer:

Chemical Formula	Number of Compounds	\(Na\)	\(Cl\)	\(C\)	\(H\)	\(O\)
\(C_{6}H_{12}O_{6}\)	\(2\)			\(12\)	\(24\)	\(12\)
\(2CaCO_{3}\)	\(1\)			\(2\)		\(6\)
\(8H_{2}O\)	\(3\)				\(16\)	\(8\)