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na (aq) + oh (aq) + h (aq) + cl (aq) → na (aq) + cl (aq) + h₂o(l) part …

Question

na (aq) + oh (aq) + h (aq) + cl (aq) → na (aq) + cl (aq) + h₂o(l)
part 3 of 4
are there any spectator ions in this reaction?
yes
no
part: 3 / 4
part 4 of 4
if you said there are spectator ions in this reaction write the net ionic equation, otherwise write na in the box below.

Explanation:

Brief Explanations

Spectator ions are ions that appear on both sides of a chemical equation and do not participate in the actual reaction. In the given equation \( \text{Na}^+(aq)+\text{OH}^-(aq)+\text{H}^+(aq)+\text{Cl}^-(aq)\to\text{Na}^+(aq)+\text{Cl}^-(aq)+\text{H}_2\text{O}(l) \), \( \text{Na}^+ \) and \( \text{Cl}^- \) are present on both sides. So, they are spectator ions. To get the net - ionic equation, we remove the spectator ions.

Answer:

  • Part 3 of 4: Yes
  • Part 4 of 4: \( \text{OH}^-(aq)+\text{H}^+(aq)\to\text{H}_2\text{O}(l) \)