Question

6 multiple choice 1 point for the reaction represented by the equation 2na + 2h₂o → 2naoh + h₂, how many grams of sodium hydroxide are produced from 3.0 mol of sodium with an excess of water? 120 g 80. g 240 g

Explanation:

Step1: Determine the mole ratio

From the balanced equation \(2Na + 2H_2O
ightarrow2NaOH + H_2\), the mole ratio of \(Na\) to \(NaOH\) is \(2:2 = 1:1\).

Step2: Calculate moles of \(NaOH\)

Given \(n(Na)=3.0\space mol\), since \(n(NaOH)=n(Na)\) (due to \(1:1\) ratio), \(n(NaOH) = 3.0\space mol\).

Step3: Calculate molar mass of \(NaOH\)

\(M(NaOH)=23 + 16+1=40\space g/mol\)

Step4: Calculate mass of \(NaOH\)

Using \(m = n\times M\), \(m(NaOH)=3.0\space mol\times40\space g/mol = 120\space g\)

Answer:

120 g