Question

9 multiple choice 1 point pds₂ palladium sulfide (ii) palladium (ii) sulfide palladium sulfide palladium (iv) sulfide

Explanation:

In naming ionic compounds with transition metals (like palladium, \(Pd\)), we need to indicate the oxidation state of the metal. Sulfide (\(S^{2 -}\)) has a charge of \(- 2\). In \(PdS_2\), let the oxidation state of \(Pd\) be \(x\). Using the charge balance formula for the compound (\(x+2\times(- 2)=0\), since the compound is neutral), we solve for \(x\):

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The naming convention for ionic compounds is \(\text{Metal (Oxidation State)} \text{Non - metal (base name + -ide)}\). So for \(PdS_2\), the name is Palladium (IV) Sulfide.

Answer:

Palladium (IV) Sulfide