Question

multiple choice 10 points
what mass of gold would require 475,500 j to increase from 70.0°c to 175°c? (s.h. of gold = 129)
693.892.000 kg
105 kg
35.1 kg
4528.6 kg

Explanation:

Step1: Recall the heat formula

The formula for heat energy \( Q \) is \( Q = mc\Delta T \), where \( m \) is mass, \( c \) is specific heat, and \( \Delta T \) is change in temperature.

Step2: Calculate \( \Delta T \)

\( \Delta T = 175^\circ C - 70.0^\circ C = 105^\circ C \)

Step3: Rearrange formula to solve for \( m \)

\( m = \frac{Q}{c\Delta T} \)

Step4: Substitute values

Given \( Q = 475500 \, J \), \( c = 129 \, J/(kg\cdot^\circ C) \), \( \Delta T = 105^\circ C \)
\( m = \frac{475500}{129 \times 105} \)
\( m = \frac{475500}{13545} \approx 35.1 \, kg \)

Answer:

35.1 Kg (corresponding to the option "35.1 Kg")