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mole - to - mass conversion if you want to calculate for the mass of an…

Question

mole - to - mass conversion
if you want to calculate for the mass of another product or reactant, this will follow the mole to mass conversion.
sample problem:
determine the mass of sodium chloride (nacl), commonly called table salt, produced when 1.25 mol of chlorine gas (cl2) reacts vigorously with excess sodium. the balanced equation is given for you. na(s) + cl2(g) → nacl(s)

Explanation:

Step1: Balance the chemical equation

The balanced equation is \(2Na(s)+Cl_{2}(g)\to2NaCl(s)\)

Step2: Determine the mole ratio

From the balanced equation, the mole ratio of \(Cl_{2}\) to \(NaCl\) is \(1:2\).

Step3: Calculate the moles of \(NaCl\)

Given \(n(Cl_{2}) = 1.25\space mol\). Using the mole ratio, \(n(NaCl)=2\times n(Cl_{2})\)
\(n(NaCl)=2\times1.25\space mol = 2.5\space mol\)

Step4: Calculate the molar mass of \(NaCl\)

The molar mass of \(Na\) is \(M_{Na}=22.99\space g/mol\) and of \(Cl\) is \(M_{Cl}=35.45\space g/mol\). So, \(M_{NaCl}=22.99 + 35.45=58.44\space g/mol\)

Step5: Calculate the mass of \(NaCl\)

Using the formula \(m = n\times M\), where \(n = 2.5\space mol\) and \(M = 58.44\space g/mol\)
\(m(NaCl)=2.5\space mol\times58.44\space g/mol = 146.1\space g\)

Answer:

The mass of \(NaCl\) produced is \(146.1\space g\)