Question

missed this? watch kcv: reaction stoichiometry; read section 8.3. you can click on the review link to access the section in your etext. for the reaction shown, calculate how many moles of no₂ form when each amount of reactant completely reacts. 2 n₂o₅ (g) → 4 no₂ (g) + o₂ (g) part c 4.87 × 10³ mol n₂o₅ express your answer using three significant figures. incorrect; try again; 3 attempts remaining

Explanation:

Step1: Find mole ratio of N₂O₅ to NO₂

From reaction: 2N₂O₅ → 4NO₂, ratio = 4/2 = 2

Step2: Calculate moles of NO₂

Moles of NO₂ = 4.87×10³ mol N₂O₅ × 2 = 9.74×10³ mol

Answer:

9.74×10³ mol