Question

1. ionic compounds
2. write the formula

(hint: must criss cross)
a) beryllium iodide
b) aluminum oxide
c) barium fluoride

1. molecular compounds
2. write the formula

a) diphosphorus trioxide
b) sulfur hexafluoride
c) dichlorine monoxide
d) iodine gas

Explanation:

Step1: Determine the ions or elements

• For ionic compounds (part 6):
• Beryllium iodide: Beryllium (\(Be^{2+}\)) and iodide (\(I^{-}\)). Using the criss - cross method, the formula is \(BeI_{2}\).
• Aluminum oxide: Aluminum (\(Al^{3+}\)) and oxide (\(O^{2 -}\)). Using the criss - cross method, the formula is \(Al_{2}O_{3}\).
• Barium fluoride: Barium (\(Ba^{2+}\)) and fluoride (\(F^{-}\)). Using the criss - cross method, the formula is \(BaF_{2}\).
• For molecular compounds (part 7):
• Diphosphorus trioxide: "di -" means 2 (for phosphorus, \(P\)) and "tri -" means 3 (for oxygen, \(O\)), so the formula is \(P_{2}O_{3}\).
• Sulfur hexafluoride: "hexa -" means 6 (for fluorine, \(F\)), so the formula is \(SF_{6}\).
• Dichlorine monoxide: "di -" means 2 (for chlorine, \(Cl\)) and "mono -" means 1 (for oxygen, \(O\)), so the formula is \(Cl_{2}O\).
• Iodine gas: Iodine exists as a diatomic molecule, so the formula is \(I_{2}\).

Answer:

6.
a) \(BeI_{2}\)
b) \(Al_{2}O_{3}\)
c) \(BaF_{2}\)
7.
a) \(P_{2}O_{3}\)
b) \(SF_{6}\)
c) \(Cl_{2}O\)
d) \(I_{2}\)