identify the number of atoms found in each chemical below:
li₂co₃
? lithium atom(s)
? carbon atom(s)
? oxygen atom(s)
al₂(no₃)₃
? aluminum atom(s)
? nitrogen atom(s)
? oxygen atom(s)

Question

Accepted Answer

# Explanation:
## Step1: Analyze $Li_2CO_3$
- For lithium ($Li$): The sub - script is $2$, so there are $2$ lithium atoms.
- For carbon ($C$): There is no sub - script, which is equivalent to a sub - script of $1$, so there is $1$ carbon atom.
- For oxygen ($O$): The sub - script is $3$, so there are $3$ oxygen atoms.

## Step2: Analyze $Al_2(NO_3)_3$
- For aluminum ($Al$): The sub - script is $2$, so there are $2$ aluminum atoms.
- For nitrogen ($N$): Inside the parenthesis, $N$ has no sub - script (equivalent to $1$), and the outer sub - script is $3$. Using the multiplication rule ($1\times3$), there are $3$ nitrogen atoms.
- For oxygen ($O$): Inside the parenthesis, the sub - script of $O$ is $3$, and the outer sub - script is $3$. Using the multiplication rule ($3\times3$), there are $9$ oxygen atoms.

# Answer:
- For $Li_2CO_3$: $2$ lithium atoms, $1$ carbon atom, $3$ oxygen atoms.
- For $Al_2(NO_3)_3$: $2$ aluminum atoms, $3$ nitrogen atoms, $9$ oxygen atoms.

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QUESTION IMAGE

Question

Explanation:

Step1: Analyze \(Li_2CO_3\)

Step2: Analyze \(Al_2(NO_3)_3\)

Answer: