Question

how much energy will it take to raise the temperature of 75.0 g of water from 20.0°c to 55.0°c? specific heat of water = 4.184 j/(g°c)
a. 63 j
b. 630 j
c. 2630 j
d. 1.1x104 j

Explanation:

Step1: Determine the formula

The formula for heat energy is \(Q = mc\Delta T\), where \(m\) is the mass, \(c\) is the specific heat capacity, and \(\Delta T\) is the change in temperature.

Step2: Identify the values

Given \(m = 75.0\ g\), \(c=4.184\ J/(g\cdot^{\circ}C)\), \(\Delta T=T_{final}-T_{initial}=55.0 - 20.0=35.0^{\circ}C\)

Step3: Substitute the values into the formula

\(Q=(75.0\ g)\times(4.184\ J/(g\cdot^{\circ}C))\times(35.0^{\circ}C)\)
First, calculate \(75.0\times4.184 = 313.8\)
Then, \(313.8\times35.0= 11083\approx1.1\times10^{4}\ J\)

Answer:

D. \(1.1\times10^{4}\ J\)