Question

how many total atoms are present in this compound? 4 zn₂sio₄ 7 24 13 28

Explanation:

Step1: Calculate atoms in one \(Zn_2SiO_4\) unit

In \(Zn_2SiO_4\), there are \(2\) Zn atoms (\(Zn_2\)), \(1\) Si atom (\(Si\)), and \(4\) O atoms (\(O_4\)). So, \(2 + 1+4=7\) atoms in one \(Zn_2SiO_4\) unit.

Step2: Multiply by the coefficient

The coefficient is \(4\). So, \(4\times7 = 28\) atoms in total.

Answer:

28