Question

how many total atoms of each element are present in the following formulas? 2 h₂so₃ + 4 h₂o tap in the fields to enter the answers directly or tap on the number pad icon to use our built - in number pad. hydrogen (h) sulfur (s) oxygen (o)

Explanation:

Step1: Calculate the number of hydrogen atoms

For \(2H_2SO_3\), the number of \(H\) atoms from this part is \(2\times2 = 4\). For \(4H_2O\), the number of \(H\) atoms from this part is \(4\times2=8\). So the total number of \(H\) atoms is \(4 + 8=12\).

Step2: Calculate the number of sulfur atoms

In \(2H_2SO_3\), the number of \(S\) atoms is \(2\times1 = 2\). There is no \(S\) atom in \(4H_2O\). So the total number of \(S\) atoms is \(2\).

Step3: Calculate the number of oxygen atoms

In \(2H_2SO_3\), the number of \(O\) atoms is \(2\times3=6\). In \(4H_2O\), the number of \(O\) atoms is \(4\times1 = 4\). So the total number of \(O\) atoms is \(6+4 = 10\).

Answer:

Hydrogen (\(H\)): \(12\)
Sulfur (\(S\)): \(2\)
Oxygen (\(O\)): \(10\)